There are 3636 chocolates in a box, all identically shaped. there 1212 are filled with nuts, 99 with caramel, and 1515 are solid chocolate. someone randomly selects one piece, eats it, and then selects a second piece. find the probability of selecting 2 nut candies. express your answer as a simplified fraction

1211/10905

Step-by-step explanation:

In the beginning, the probability to pick a nut piece is 1212/3636. Once you eat it you have 3635 candies left, of which 1211 are nuts, and therefore the probability to pick nut again is 1211/3635.

So, the combined probability is 1212/3636 * 1211/3635 = 1/3 * 1211/3635 = 1211/(3*3635) = 1211/10905

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )