Elly has 2 rectangular gardens. one measures 1809 cm by 2891 cm and the other measures 738 cm by 249 cm. elly wants to put a fence around both, how much does she need to buy?

She needs 11374 cm to buy

Step-by-step explanation:

* Lets explain how to solve the problem

- The dimensions of the first rectangle is 1809 cm and 2891 cm

- The dimensions of the first rectangle is 738 cm and 249 cm

- Elly wants to put a fence around both

- To find the length of the fence calculate the perimeters of the two

 rectangles

- The perimeter of the rectangle = 2(b + h), where b , h are the

 dimensions of the rectangle

# First rectangle

∵ The dimensions are 1809 cm and 2891 cm

∵ P = 2(b + h)

∴ P = 2(1809 + 2891) = 2(4700) = 9400 cm

# Second rectangle

∵ The dimensions are 738 cm and 249 cm

∵ P = 2(b + h)

∴ P = 2(738 + 249) = 2(987) = 1974 cm

∵ The length of the fence = the sum of the perimeters of the two

  rectangles

∴ The length of the fence = 9400 + 1974 = 11374 cm

* She needs 11374 cm to buy

the answer is 45 i just did it on oddesy ware

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: