The driver of a car traveling at 60 ft/sec suddenly applies the brakes. the position of the car is s(t) = 60t − 1.5t2, t seconds after the driver applies the brakes. how many seconds after the driver applies the brakes does the car come to a stop?

20 seconds

Step-by-step explanation:

Given:

Position of car = s(t) = 60t-1.5t^2

The speed is the change in position.

So,

When the car will stop, the speed will be zero.

Therefore, the car will stop after 20 seconds of applying the break ..

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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i dont know sorry

step-by-step explanation: