Aboy has 40 red and blue pencils in his pencil case. if the ratio of red to blue pencils is 0.15 to 0.35, how many blue pencils does he have?

The boy has 28 blue pencils

Step-by-step explanation:

Given

Total pencils = 40

The ratio of red to blue= 0.15:0.35

We have to find the number of blue pencils

For that we need the sum of ratio = 0.15+0.35 = 0.5

So, the number of blue pencils = (ratio of blue/sum of ratio) * total pencils

=0.35/0.5 * 40

=0.7*40

=28 pencils

Therefore, the boy has 28 blue pencils ..

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

idk

step-by-step explanation:

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