At a certain distance fro a pole, the angle of elevation to the top of the pole is 28 degrees. if the pole is 6.3 feet tall, what is the distance fro the pole?

The distance from the pole is 11.8 ft

Step-by-step explanation:

Let

x> the distance from the pole

we know that

The tangent of angle of 28 degrees is equal to divide the opposite side to angle of 28 degrees ( the height of the pole) by the adjacent side to angle of 28 degrees ( the horizontal distance from the pole)

so

tan(28°)=6.3/x

Solve for x

x=6.3/tan(28°)=11.8 ft

a

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: