Which equations could be used to solve for the unknown lengths of △abc? check all that apply.
sin(45°) =  
sin(45°) =  
9 tan(45°) = ac 
(ac)sin(45°) = bc
cos(45°) =  

sin(45°)= AC/9

cos(45°)= BC/9

Step-by-step explanation:

This is a right angle triangle:

∠ABC =∠CAB = 45°

Now

AC= CB

AB = 9 units.

We will apply sines:

sine(45°)= AC/AB

We know that AB = 9 units.

So substitute the value of side AB

sin(45°)= AC/9

Now apply cos(45°)

cos(45°)=  BC/AB

Again substitute the value of AB:

cos(45°)= BC/9

Thus the answer is

sin(45°)= AC/9

cos(45°)= BC/9  ....

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x