Five consecutive multiples of 3 yield a sum that is equal to the product of 7 and 15. what are these multiples?

15, 18, 21, 24, 27

Step-by-step explanation:

Five multiples of 3 means we have 5 terms we are adding together to = 105.

For the sake of having something to base each one of these terms on, let's say that the first term is 3.  It's not, but 3 is a multiple of 3 and we have to start somewhere.  These terms go up by the next number that is divisible by 3.  After 3, the next number that is divisible by 3 is 6.  The next one is 9, the next is 12, the last would be 15.

Let's then say that 3 is the first term, and we are going to say that is x.

To get from 3 to 6, we add 3.  Therefore, the second term is x + 3.

To get from 3 to 9, we add 6.  Therefore, the third term is x + 6.

To get from 3 to 12, we add 9.  Therefore, the fourth term is x + 9.

To get from 3 to 15, the last term, we add 12.  Therefore, the last term is x + 12.

The sum of these terms will then be set to equal 105:

x + (x + 3) + ( x + 6) + ( x + 9) + ( x + 12) = 105

We don't need the parenthesis to simplify so we add like terms to get

5x + 30 = 105.  Subtract 30 from both sides to get

5x = 75 so

x = 15

That means that 15 is the first multiple of 3.  

The next one is found by adding 3 to the first:  so 18

The next one is found by adding 6 to the first:  so 21

The next one is found by adding 9 to the first:  so 24

The last one is found by adding 12 to the first:  so 27

15 + 18 + 21 + 24 + 27 = 105

Notice that all the numbers are, in fact, consecutive multiples of 3 as the instructions stated.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

29933333.33

step-by-step explanation: