The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous ran- dom variable with a cumulative distribution function f(x)= 0, x< 0, 1−e−4x, x≥0. find the probability of waiting fewer than 12 minutes between successive speeders.

0.5507

Step-by-step explanation:

Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function

Since , the waiting time is in hours , then we can write 12 minutes as hour i.e.0.2 hour.

Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-

Hence, the required probability = 0.5507

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

6mm^3 or .6cm^3

      216

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  36     6

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6     6   6

factor trees are nice.