Find a solution for the following recurrence relation and initial conditions (use the method of characteristic equation): di = 6d-1-9d1-2, for all integers k> 2; do -1, di = 4. dk=d3k+bk3k do=1=d30+b*0*39=d> d=1 d1=4=d31=3d+3b → d+b=4/3 +b=4/3=d=4/3-154-3/3=1/3 final: dx=3kk3*

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step-by-step explanation:

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the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.