Aresearcher wishes to estimate the proportion of adults who have high-speed internet access. what size sample should be obtained if she wishes the estimate to be within 0.04 with 90% confidence if (a) she uses a previous estimate of 0.38? (b) she does not use any prior estimates?

a-396

b-420

Step-by-step explanation:

=0.1

Margin of Error=0.04

Level of significance is z

Previous estimate

sample size is given by:

n=

n=

Does not use prior estimate

Assume

=0.1

Margin of Error=0.04

Level of significance is z

Population proportion=0.5

n=

n=

n=420.25

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)