The box plots show the weights, in pounds, of the dogs in two different animal shelters.
weights of dogs in shelter a
weights of dogs in shelter b
which is true of the data in the box plots? check all that apply.
the median weight for shelter a is greater than that for shelter b.
the median weight for shelter b is greater than that for shelter a.
the data for shelter a are a symmetric data set.
the data for shelter b are a symmetric data set.
the interquartile range for shelter a is 8.

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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25% is the answer

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

i believe it’s 165 because if u add 137 and 58 u get 195 and then subtract that from 360 and there’s ur answer