What is the equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3)?
5 x - 6 y - 8 = 0
3 y = -2x + 20
y=5/6 x-4/3

y = 5/6x -4/3

Step-by-step explanation:

We can find the slope

m = (y2-y1)/(x2-x1)

    = (-3-2)/(-2-4)

    =-5/-6

    = 5/6

We can use point slope form to find the equation

y-y1 = m(x-x1)

y-2 = 5/6(x-4)

Distribute

y-2 = 5/6x - 10/3

Add 2 to each side

y-2+2 = 5/6x -10/3+2

Get a common denominator

y = 5/6x -10/3 +6/3

y = 5/6x -4/3

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's