These dot plots show the weights (in kilograms) from a sample of leopards and tigers

and are correct.

Further explanation:

Spread can also be calculated by range, as the range is a measure of spread.

Range can be calculated as,

Range = Maximum Value - Minimum Value.

Maximum weight of leopards is .

Minimum weight of leopards is .

Range =

Range =

Maximum weight of tigers is .

Minimum weight of tigers is .

Range =

Range =

Range of the tigers is more than the range of leopards.

Therefore, the weights of tigers are more spread out.

Median is the middle value. data points lie below the median and data points lie above the median.

The number of leopards are and the number of observations are even.

Therefore, the median weight of leopards can be calculated as,

Median weight of leopards is the mean

Median weight of leopards is the mean

Median weight of leopards is the mean

The and the

Median weight of leopards =

Median weight of leopard is .

The number of tigers are and the number of observations are odd.

Therefore, the median of leopards can be calculated as,

Median weight of tigers is

Median of leopards is

Median weight of tigers is

is

Median weight of tigers =

Median weight of tigers is greater than median weight of leopard.

Therefore, the leopards have lower median weight than the tigers.

Hence, and are correct.

Learn More:

1. Learn more about addition

2. Learn more about trinomial

Answer Details:

Grade: Middle School

Subject: Mathematics

Chapter: Statistics

Keywords:

Probability, Statistics, Median, Mode, Range, Spread, Mean, Standard deviation, Symmetric, Odd, Even, Variance, Tigers, Leopards.

Center:The leopards have a lower median weight that the tigers. and Spreads: The weights of the tigers are more spread out.

Step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!