Circle o is represented by the equation (x + 7)^2 + (y + 7)^2 = 16. what is the length of the radius of circle o?

4

Step-by-step explanation:

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

where (h,k) is the center and

r is the radius.

You compare your equation to mine you should see that:

-h=7 implies h=-7

-k=7 implies k=-7

r^2=16 implies r=4 since 4^2=16

The center is (-7,-7).

The radius is 4.

For this case we have that by definition, the equation of a circle in standard or canonical form is given by:

Where:

(h, k) is the center

r: It's the radio

We have the following equation:

Thus, the radius is 4.

4

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i