An oil refinery is located 1 km north of the north bank of a straight river that is 2 km wide. a pipeline is to be constructed from the refinery to storage tanks located on the south bank of the river 9 km east of the refinery. the cost of laying pipe is $500,000/km over land to a point p on the north bank and $1,000,000/km under the river to the tanks. to minimize the cost of the pipeline, how far downriver from the refinery should the point p be located? (round your answer to two decimal places.)
km

  7.86 km

Step-by-step explanation:

Let x represent the distance point P lies east of the refinery. (We assume this direction is downriver from the refinery.)

The cost of laying pipe to P from the refinery (in millions of $) will be ...

  0.5√(1² +x²)

The cost of laying pipe under the river from P to the storage facility will be ...

  1.0√(2² +(9-x)²) = √(85 -18x +x²)

We want to minimize the total cost c. That total cost is ...

  c = 0.5√(x² +1) +√(x² -18x +85)

The minimum value is best found using technology. (Differentiating c with respect to x results in a messy radical equation that has no algebraic solution.) A graphing calculator shows it to be at about x ≈ 7.86 km.

Point P should be located about 7.86 km downriver from the refinery.

go on the tube you might find some information there

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4