In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

{ x ∈ R | x ≥  9 }

Step-by-step explanation:

we have

solve for x

Adds 7 both sides

Divide by 2 both sides

The solution is the interval -----> [9,∞)

In set builder notation

{ x ∈ R | x ≥  9 }

All real numbers greater than or equal to 9

answer: 7270

step-by-step explanation:

move it to the other side

step-by-step explanation: