![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2-9 \\\\\\ \textit{we also know that } \begin{cases} x=0\\ y=-6 \end{cases}\implies -6=a(0-1)^2-9\implies 3=a(-1)^2](/tpl/images/0098/7760/4559b.png)
![\bf 3=a\qquad \qquad \textit{therefore}\qquad \qquad \boxed{y=3(x-1)^2-9} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{y}{0}=3(x-1)^2-9\implies 9=3(x-1)^2\implies \cfrac{9}{3}=(x-1)^2\implies 3=(x-1)^2 \\\\\\ \pm\sqrt{3}=x-1\implies \pm\sqrt{3}+1=x\implies x= \begin{cases} \sqrt{3}+1\\ -\sqrt{3}+1 \end{cases}\implies x\approx \begin{cases} 2.73\\ -0.73 \end{cases}](/tpl/images/0098/7760/1d1f5.png)
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find the x-intercepts of the parabola with vertex (1,-9) and y-intercept at (0,-6).
a...
Mathematics, 17.07.2019 04:20 JohnBranks3258
17
find the x-intercepts of the parabola with vertex (1,-9) and y-intercept at (0,-6).
a. (-1,0), (3,0)
b. (-0.73,0), (2.73,0)
c. (-1.48,0), (2.48,0)
d. (-4.67,0), (1.67,0)
Answers: 2
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