Using the discriminant, how many real solutions does the following quadratic
equation have?
x^2 - 8x + 16 = 0
a. three real solutions
b. no real solutions
c. two real solutions
d. one real solution

D one real solution

Step-by-step explanation:

x^2 - 8x + 16 = 0

This is in the form

ax^2 +bx + c = 0

so we can use the discriminant to determine the number of solutions

b^2 -4ac

(-8)^2 -4(1)(16)

64 - 64

0

Since the discriminant is zero, there is one real solution.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

it's