What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
quadratic formula: x=
-divo? - 400
20

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  f(x) = x^2 + 5x + 5.

Start the solution by finding the discriminant of this quadratic:  a = 1, b = 5 and c = 5.  Then the value of the discriminant b^2 - 4ac is  25-4(1)(5) = 5.

Because the discriminant is positive, we know that there are two real, unequal  roots.  They are:

      -5 ± √5                   -5 + √5                       -5 - √5

x = , or x =   and   x =

           2                              2                                  2

all it means is function 3