What are the zeros of the function below ? check all that apply. f(x)= 5(x+2)/3(x-1)(x+7)

-2 is a zero if your function is

Please correct me if I'm wrong.

Step-by-step explanation:

Assuming you meant

the zeros are what makes the numerator 0 (any zeros of the top that are also zeros of the bottom should be excluded).

Anyways we just need to find when 5(x+2) is 0.

5(x+2)=0

Divide by 5 on both sideS:

x+2=0

Subtract 2 on both sides:

x=-2

And -2 doesn't make the bottom 0.

Checking to see :   3(-2-1)(-2+7)=3(-3)(5)=-9(5)=-45 (not 0).

So F has zero -2.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.