Find the average rate of change of the function
f(x) = √x +1 on the interval 4 ≤ x ≤ 9. recall that
the coordinates for the start of the interval are (4,
3).
what are the coordinates for the end of the
interval?
o (9,4)
o (9,3)
o (9, 82)

A function describes the relationship between related variables.

Given that:

The average rate of change (m) is calculated as:

So, we have:

Calculate f(4)

Calculate f(9)

So, we have:

Recall that:

--- this represents the coordinate of the start interval

--- this represents the coordinate of the end interval

Hence, the coordinates of the end interval is (9,4)

Read more about average rates of change at:

link

Oops I went too far.

The other point is (9,4).

The average rate of change is 1/5.

Step-by-step explanation:

So I think your function is . Please correct me if I'm wrong.

You want to find the slope of the line going through your curve at the points (4,f(4)) and (9,f(9)).

All f(4) means is the y-coordinate that corresponds to x=4 and f(9) means the y-coordinate that corresponds to x=9.

So if , then

and

.

So your question now is find the slope of the line going through (4,3) and (9,4).

You can use the formula but I really like to just line up the points vertically and subtract then put 2nd difference over 1st difference. Like this:

( 9  ,   4)

-( 4  ,   3)

-------------

 5         1

So the slope is 1/5.

The average rate of change of the function f on the interval [4,9] is 1/5.

i think it is 18

step-by-step explanation: