Asurvey asked, "during the last year, did anyone take something from you by using force-such as a stickup, mugging, or threat? " of 987 subjects, 19 answered yes and 968 answered no. a. find the point estimate of the proportion of the population who were victims. b. find the standard error of this estimate. c. find the margin of error for a 95% confidence interval. d. construct the 95% confidence interval for the population proportion. can you conclude that fewer than 10% of all adults were victims?

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.

answer

a) the midrange of the data set shown is 85.5

step by step explanation

let's find the midrange.

the midrange is nothing but add the greatest value and the least value, then divide it by 2.

here the greatest value = 99

the least value = 72

midrange = (99 + 72)/2

= 171/2

midrange = 85.5

you.