Which are the solutions of x^2 = -13x – 4?

Step-by-step explanation:

Rewrite this equation in standard quadratic form:  x^2 + 13x + 4 = 0.

Here the coefficients are 1, 13 and 4, so the discriminant is

b^2-4ac, or 169 - 4(1)(4) = 153

Since the discriminant is + there are two real, unequal roots.  They are:

       -13 ± √153

x =  

            2

x =

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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correct answer is b. 27/8

step-by-step explanation: