Which factor could be part of the function so that the function is increasing on the left and decreasing on the right? select all
that apply.
f(x) = (x+ 5)
options are:
-0.8
-3x
(x+5)
-(2x+1)
(3x^2+5)

Only C

Step-by-step explanation:

Recall from the properties of end behaviors of polynomials, that:

a) if the lead coefficient is negative, the end behavior on the right side has a negative slope (and vice versa), also

b) if the degree is even, then the end behavior of the left side must be pointing in the same vertical direction as the right side.

Back to the question:

Hence to have the left side increasing and the right side decreasing, we can conclude that based on the above properties, that.

a) since the right side is decreasing (negative slope), hence the polynomial must have a lead coefficient that is negative.

b) since one side of the graph is increasing, and the other side is decreasing, the function must look roughly like an "n" shape, which means that the end behavior of both the left and right side points downward. Hence the degree of the polynomial is EVEN.

so

f(x) = (x+4)(- 5)

f(x) = -5x - 20

all we need to do is go down the list and multiply f(x) with the options and see which one fits the 2 criteria we determined above.

A) f(x) . (-0.8) = (-5x -20)(-0.8) = 4x + 16 (positive lead coeff. and odd degree, Does Not Aply)

B) f(x) . (-3x) = (-5x -20)(-3x) = 15x² + 60 (positive lead coeff. and even degree, Does not apply)

C) f(x) . (x+5) = (-5x -20)(x+5) = -5x² - 45x - 100 (negative lead coeff, even degree THIS APPLIES!)

I'm not going to work out the last 2, but they give

D) f(x) . -(2x+1) = 10x²+45x+20 (positive lead coeff, even degree, Does not apply)

E) f(x) . (3x²+5) = −15x³−60x²−25x−100 (negative lead coeff, odd degree, Does not apply)

Hence only C applies

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true