Which is the equation of a line with a slope
of 1 and a y-intercept of 2?
(1) y + x = 2 (3) y - x + 2 = 0
2) y - x = 2 (4) y + x - 2 = 0

2) y-x=2

Add x on both sides:

 y        =x+2

The slope is 1 and the y-intercept is 2.

Step-by-step explanation:

So a linear equation in slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

Let's put all of these in that form:

1) y+x=2

Subtract x on both sides:

 y     =-x+2

The slope is -1 and the y-intercept is 2.

2) y-x=2

Add x on both sides:

 y        =x+2

The slope is 1 and the y-intercept is 2.

3) y-x+2=0

Add x on both sides:

 y     +2=x

Subtract 2 on both sides:

 y        =x-2

The slope is 1 and the y-intercept is -2.

4) y+x-2=0

Add 2 on both sides:

 y +x      =2

Subtract x on both sides:

 y           =-x+2

The slope is -1 and and the y-intercept is 2.

answer: e 9, 5.75

step-by-step explanation:

step 1

find the variation ab in the x coordinate

delta x=(x2-x1)=10-> 8 units

find the variation ab  in the y coordinate 

delta y=(y2-y1)=6-> 2 units

step 2

find the coordinates point c

  x coordinate 

cx=ax+delta x*2/> cx=2+8*(2/> cx=3

  y coordinate 

cy=ay+delta y*2/> cy=4+2*(2/> cy=4.25

the coordinates of point c are (3,4.25)

step 3

find the coordinates point d

  x  coordinate 

dx=ax+delta x*4/> dx=2+8*(4/> dx=4

  y  coordinate 

dy=ay+delta y*4/> dy=4+2*(4/> dy=4.5

the coordinates of point d are (4, 4.5)

step 4

find the coordinates point e

  x  coordinate 

ex=ax+delta x*4/> ex=2+8*(6/> ex=5

  y  coordinate 

ey=ay+delta y*4/> ey=4+2*(6/> ey=4.75

the coordinates of point e are (5, 4.75)

step 5

find the coordinates point f

  x  coordinate 

fx=ax+delta x*4/> fx=2+8*(8/> fx=6

  y  coordinate 

fy=ay+delta y*4/> fy=4+2*(8/> fy=5

the coordinates of point f are (6,5)

step 6

find the coordinates point g

  x  coordinate 

gx=ax+delta x*4/> gx=2+8*(10/> gx=7

  y  coordinate 

gy=ay+delta y*4/> gy=4+2*(10/> gy=5.25

the coordinates of point g are (7,5.25)

step 7

find the coordinates point h

  x  coordinate 

hx=ax+delta x*4/> hx=2+8*(12/> hx=8

  y  coordinate 

hy=ay+delta y*4/> hy=4+2*(12/> hy=5.5

the coordinates of point h are (8,5.5)

step 8

find the coordinates point i

  x  coordinate 

ix=ax+delta x*4/> ix=2+8*(14/> ix=9

  y  coordinate 

iy=ay+delta y*4/> iy=4+2*(14/> iy=5.75

the coordinates of point i are (9,5.75)

- r3ktforgood ☕

what graph

step-by-step explanation: