if 0 < b ≤ 90 and cos(11b + 2) = sin(12b − 4), what is the value of b?
b = 3
b = 4
b = 5
b = 6

4

Step-by-step explanation:

You can plug in the b's and see.  You can also try to use a co-function identity and get a value for b that way.

Let's try the co-function identity:

sin(x)=cos(90-x).

First step:

cos(11b+2)=cos(90-[12b-4])

 So one set of solutions can be found by solving:

11b+2=90-[12b-4]

Distribute:

11b+2=90-12b+4

Add 12b on both sides

23b+2=90+4

Simplify:

23b+2=94

Subtract 2 on both sides:

23b     =94-2

23b      =92

Divide both sides by 23:

  b=       92/23

  b=        4

So 4 is one value that will work.

there are no figures how am i supposed to answer this question

step-by-step explanation:

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13