Questions (no partial grades if you don't show your work) 1. in a group of 6 boys and 4 girls, four children are to be selected. in how many diffeest weys ces they be selected if at least one boy must be there

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = =24

2 Boy and 2 girls=

3 Boys and 1 girl =

4 Boys =

Now total number of ways = 24 + 90 + 80 + 15 = 209

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3