![Expected\ value=E\left [ x \right ]=\sum _{i=1}^{k} x_{i}p_{i}](/tpl/images/0083/6100/c0290.png)
![E\left [ x \right ]=4\times 0.1+3\times 0.2+2\times 0.4+1\times 0.2+0\times 0.1\\\therefore E\left [ x \right ]=2](/tpl/images/0083/6100/7b5dc.png)
![Var\left ( x\right)=E\left [ x^2 \right ]-E\left [ x \right ]^2](/tpl/images/0083/6100/8484f.png)
![E\left [ x^2 \right ]=4^2 \times 0.1+3^2 \times 0.2+2^2 \times 0.4+1^2 \times 0.2+0^2 \times 0.1\\\Rightarrow E\left [ x^2 \right ]=5.2\\E\left [ x \right ]^2=2^2=4\\\therefore Var\left ( x\right)=5.2-4=1.2\\](/tpl/images/0083/6100/d88c6.png)
Ineed this done in an excel spreadsheet with solutions
the following probabilities for grades...
Mathematics, 13.07.2019 05:10 Crxymia
Ineed this done in an excel spreadsheet with solutions
the following probabilities for grades in management science have been determined based on past records:
grade probability
a 0.1
b 0.2
c 0.4
d 0.2
f 0.10
the grades are assigned on a 4.0 scale, where an a is a 4.0, a b a 3.0, and so on.
determine the expected grade and variance for the course.
Answers: 3
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