Determine the solution and sketch the area of solutions of the given inequalities. 1)y 4x 3 y -2x 3 > 2) y -5x 3; y> -2 3) y 3 ys-x+ 1

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.