What are the two cases in which the laws of sines can be applied to solve a non-right triangle?
case i. you know the measures of two angles and any side of the triangle.
case ii. you know the measures of two sides and an angle opposite one of the two known sides.
case iii. you know the measures of two sides and the included angle.
case iv. you know the measures of all three sides.

  Case I, Case II

Step-by-step explanation:

For cases III and IV, you need the Law of Cosines.

The Law of Sines can be used when you have at least one side and the angle opposite. If you know two angles of a triangle, you know all three, so the given angles don't necessarily have to be opposite the given side if two angles are known.

The Laws of Sines can be applied to solve Case I and Case II.

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is