Acompany is replacing cables with fiber optic lines in rectangular casing bcde. if line segment de = 3 cm and line segment be = 3 cm, what is the smallest diameter of pipe that will fit the fiber optic line? round your answer to the nearest hundredth.
3.54 cm
3.91 cm
4.24 cm
4.95 cm

Based on the information given, the smallest diameter will be C. 4.24 cm.

DB² = 3² + 3²

DB² = 9 + 9

DB² = 18

DB = ✓18

DB = 4.24

Therefore, the correct option is 4.24.

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The correct option is C.

Step-by-step explanation:

Given information: BCDE is a rectangular casing, DE = 3 cm and BE = 3 cm.

We need to find the smallest diameter of pipe that will fit the fiber optic line. It means we have to find the measure of DB.

The measure of all interior angles of a rectangle or square is 90°.

It means the DEB is right angled triangle.

According to the Pythagoras theorem:

In triangle DEB,

Taking square root both sides.

Therefore the correct option is C.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm