The height y (in feet) of a ball thrown by a child is
y=−1/12x^2+4x+3
where x is the horizontal distance in feet from the point at which the ball is thrown.
(a) how high is the ball when it leaves the child's hand? (hint: find y when x=0)
your answer is y=
(b) what is the maximum height of the ball?
(c) how far from the child does the ball strike the ground?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?