Use the graph of f to describe the transformation that results in the graph of g.
f(x) = ; g(x) =

question 5 options:
g(x) is the graph of f(x) translated 1 unit(s) to the and 5 unit(s) .
g(x) is the graph of f(x) translated 5 unit(s) to the and 1 unit(s) .
g(x) is the graph of f(x) translated 1 unit(s) to the and 5 unit(s) .
g(x) is the graph of f(x) translated 5 unit(s) to the and 1 unit(s) .

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )