The fashion store has ? $12,000 available each month for advertising. newspaper ads cost ? $600 apiece and no more than 40 can be run per month. radio ads cost ? $300 each and no more than 50 can run per month. tv ads cost ? $1800 a? piece, with a maximum of 6 available each month. approximately 3000 women will see each newspaper? ad, 1800 will hear each radio? ad, and 14,000 will see each tv ad. how much of each type of advertising should be used if the store wants to maximize? exposure? how many news paper ads should be placed?

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.