Mathematics, 10.07.2019 02:10 KindaSmartPersonn
Derive the equation of the parabola with a focus at (β5, β5) and a directrix of y = 7. f(x) = βone twenty fourth(x β 1)2 β 5 f(x) = one twenty fourth(x β 1)2 β 5 f(x) = βone twenty fourth(x + 5)2 + 1 f(x) = one twenty fourth(x + 5)2 + 1
Answers: 3
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Given right triangle a w/a hypotenuse length of x+4 and a leg of x, and right triangle b, w/ a hypotense length of 3y and a leg length of y+4 for what values of x and y are the triangles congruent by hl?
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Derive the equation of the parabola with a focus at (β5, β5) and a directrix of y = 7. f(x) = βone t...
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