1. for all these problems, it is important to show your work. each problem should be carefully set up and all steps leading to a solution provided. joey's wedding reception had 60 members of his family, 30 members of his wife's family and 20 friends in attendance. a group of six was selected by the dj to participate in a dance. you must set up your problem in combinatorics format and then simplify completely. what is the probability that: two of his family, two of his new wife's family and two of their friends a. are chosen? b. at least one of joey's family is selected? at most four of their friends are selected? c. d. all selected dancers are from the same category (joey's family, his wife's family or their friends)?

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0

first 15 divide by 2 = 7.5

100 divided by 7.5 is 13.

15 / 2 = 7.5

100 / 7.5 = 13.