Will get brainliest if explained and correct
give the equation for a circle with the given center and radius.
center at (-1, 3), radius = 4
a. (x+3)2+(y−1)2=4
b. (x−3)2+(y+1)2=4
c. (x−1)2+(y+3)2=16
d. (x+1)2+(y−3)2=16

D.

Step-by-step explanation:

We are asked to write equation of a circle whose center is at point and whose radius is 4 units.

We know that equation of a circle is standard form is in format , where is the center of circle.

Upon substituting , and in the standard form of circle, we will get:

Therefore, our required equation would be and option D is the correct choice.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

p = 6s

step-by-step explanation: