:(
determine the number of solutions for the quadratic function f(x) = 3x^2 + 5x + 10.

0 real solutions

Step-by-step explanation:

I guess you are looking for the number of real solutions? Correct me if I'm wrong.

There is something called the discriminant that can help us determine this without actually solving f(x)=0 for x.

The discriminant is the thing inside the square root in the quadratic formula.

It is the thing that reads b^2-4ac.

If b^2-4ac:

A) is negative, then you have 0 real solutions (you could say 2 complex solutions)

B) is positive, then you have 2 real solutions

C) is 0, then you have 1 real solution

So comparing 3x^2+5x+10 to ax^2+bx+c, you should see that a=3, b=5, and c=10.

b^2-4ac

=5^2-4(3)(10)

=25-120

=-95

That is a negative result so you have no real solutions.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: