On a certain exam, tony corrected 2020 papers and found the mean for his group to be 6060. alice corrected the remaining 1010 papers and found that the mean for her group was 8080. what is the mean of the combined group of 3030 students

The mean is 66.667 ( approx )

Step-by-step explanation:

Let x be the sum of Tony's group and y be the sum of Alice's group,

We know that,

According to the question,

In Tony's group,

Students = 20,

Mean = 60,

In Alice's group,

Students = 10,

Mean = 80,

Thus, the total sum of combined group of 30 students = 1200 + 800 = 2000,

Hence, the mean of the combined group =

x is the total time in minutes for the free response

you are given number of questions as 15 - m and time per item as 8 minutes

to find x multiply the two givens together:

x = 8 * (15-m) = 8(15-m)

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.