According to a study published in a reputable science magazine, about 8 women in 100,000 have cervical cancer (c), so p(c)equals0.8 and p(no c)equals0.2. the chance that a pap smear will incorrectly indicate that a woman without cervical cancer has cervical cancer is 0.04. therefore, upper p left parenthesis test pos|no upper c right parenthesisequals0.04. what is the probability that a randomly chosen woman who has this test will both be free of cervical cancer and test positive for cervical cancer (a false positive)?