Acar dealership has 6 red, 9 silver, and 3 black cars on the lot. six cars are randomly chosen to be displayed in front of the dealership. find the probability that 3 cars are red and 3 are black. 0.001077 (round to six decimal places as needed.)

Hence, our required probability is 0.001077.

Step-by-step explanation:

Since we have given that

Number of red cars = 6

Number of silver cars = 9

Number of black cars = 3

Total number of cars = 6+9+3=18

We need to find the probability that 3 cars are red and 3 are black.

So, the required probability is given by

Hence, our required probability is 0.001077.

the answer would be the last one (constat) she stays at the same rat every two mintues it goes up by 0.4

step-by-step explanation:

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