For each n = 1,2,3, define fn(x)x(1- t), for every e (-1,1]. let f : r2-r be defined by f(2, y)) = x2e 2 2y, for every (x, y) e r2. then the function fdefined by f(x): = lim fn(x) f(0,0)) + fm (0,0)) is: the value of f((0,0)) + noo exists for each x e [-1,1] and is equal to select one: select one: undefined f(x) 0 a = 1 -2 o 0 f(x)= 0 o a

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: