From a shipment of 65 transistors, 6 of which are defective, a sample of 5 transistors is selected at random.
(a) in how many different ways can the sample be selected?

(b) how many samples contain exactly 3 defective transistors?

(c) how many samples do not contain any defective transistors?
samples

a) 8259888

b) 34220

c) 45057474

Step-by-step explanation:

Given,

The total number of transistor = 65,

In which, the defective transistor = 6,

So, the number of non defective transistor = 65 - 6 = 59,

Since, out of these transistor 5 are selected,

a) Thus, the number of ways = the total possible combination of 5 transistors =

b) The number of samples that contains exactly 3 defective transistors = the possible combination of exactly 3 defective transistors =

c) The number of sample without any defective transistor = The possible combination of 0 defective transistor =

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this