Part ii: let l: r-> r2 be the linear transformation defined by l u find ker l hint: to find the ker l, we must determine all v in r3 so that l (v) =0 r2 (0 is the zero vector)

well your weight will go up if you are not going to burn the calories/ carbs

step-by-step explanation:

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b