The mean ages with standard deviations of four swim teams at a swim club are given below.
team
mean
standard deviation
stars
16
4.1
dolphins
18
1.5
giants
14
0.3
mackerels
15
2.3
which statement is most likely to be true?
the ages of the mackerels are the most dispersed from the team’s mean.
the ages of the stars are the most dispersed from the team’s mean.
the ages of the dolphins are the most dispersed from the team’s mean.
the ages of the giants are the most dispersed from the team’s mean.

Statement 2 (The ages of the Stars are the most dispersed from the team’s mean).

Step-by-step explanation:

Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data. Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion. In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true i.e. the option 2!!!

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.

1

step-by-step explanation:

it's the only multiple of both and the least