If the sum of five consecutive odd integers is 265, what is the smallest of the five integers?

The smallest integer = 49

Step-by-step explanation:

It is given that, the sum of five consecutive odd integers is 265

To find the smallest integer

Let 'x' be the smallest odd  integer, the other integers are,

(x + 2), (x + 4), (x + 6), and (x + 8)

x + x + 2 + x + 4 + x + 6 + x + 8 = 265

5x + 20 = 265

5x = 245

x = 245/5 = 49

Therefore the smallest integer = 49

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.