What are the zeros of the function f(x)=x^2+x-6 divides by x^2-x-6?

It is B.

Step-by-step explanation:

x^2+x-6 /  x^2-x-6 = 0

The numerator equates to zero:

x^2 + x - 6 = 0

(x + 3)(x - 2) = 0

the zeroes are {-3, 2).

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day