From the top of a mountain, i could see a town at an angle of depression of 1.4◦ across the level plain. looking at my map i found that the town was 10 km away. find the height of the mountain above the plain, to the nearest metre.
someone explain to me how they get the answer for this!

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i think it is 18

step-by-step explanation:

do you have a picture of the table

mia khalifa

step-by-step explanation: