Which of the following is a solution to the second order differential equation latex: y''=-4y y ″ = − 4 y ? to answer this question, attempt to verify each of the following proposed solutions. a. latex: y=\sin2t y = sin ⁡ 2 t b. latex: y=-\frac{2}{3}t^3 y = − 2 3 t 3 c. latex: y=\cos2t y = cos ⁡ 2 t d. latex: y=e^{2t} y = e 2 t e. latex: y=\frac{y''}{-4}

Step-by-step explanation:

In the case of each of the answers listed above, the second derivative is equal to -4 times the function, as required by the differential equation.

For y = 2/3t^3, the second derivative is 4t, not -4y.

For y = e^(2t), the second derivative is 4y, not -4y.

__

The graph shows the sum of the second derivative and 4y is zero for the answers indicated above, and not zero for the other two proposed answers.

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: