Refer to the accompanying data set and use the 30 screw lengths to construct a frequency distribution. begin with a lower class limit of 0.470 in, and use a class width of 0.010 in. the screws were labeled as having a length of 1 divided by 2 in. does the frequency distribution appear to be consistent with the label? why or why not?
screw lengths (inches)
0.478
0.503
0.507
0.478
0.488
0.493
0.508
0.479
0.506
0.502
0.509
0.493
0.495
0.485
0.509
0.505
0.498
0.485
0.497
0.485
0.498
0.515
0.501
0.502
0.497
0.489
0.509
0.491
0.505
0.499
complete the frequency distribution below

step-by-step explanation:

if x = 2 you have to find x to finish the problem

the answer is c hope this

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200